BitArray.And(BitArray) メソッド

public:
 System::Collections::BitArray ^ And(System::Collections::BitArray ^ value);

public System.Collections.BitArray And(System.Collections.BitArray value);

member this.And : System.Collections.BitArray -> System.Collections.BitArray

Public Function And (value As BitArray) As BitArray

パラメーター

返品

現在の BitArray オブジェクトへの参照であるビットごとの AND 演算の結果を含む配列。

例外

例

次のコード例は、2 つの BitArray オブジェクト間でビットごとの AND 演算を実行する方法を示しています。

using System;
using System.Collections;
public class SamplesBitArray  {

   public static void Main()  {

      // Creates and initializes two BitArrays of the same size.
      BitArray myBA1 = new BitArray( 4 );
      BitArray myBA2 = new BitArray( 4 );
      myBA1[0] = myBA1[1] = false;
      myBA1[2] = myBA1[3] = true;
      myBA2[0] = myBA2[2] = false;
      myBA2[1] = myBA2[3] = true;

      // Performs a bitwise AND operation between BitArray instances of the same size.
      Console.WriteLine( "Initial values" );
      Console.Write( "myBA1:" );
      PrintValues( myBA1, 8 );
      Console.Write( "myBA2:" );
      PrintValues( myBA2, 8 );
      Console.WriteLine();

      Console.WriteLine( "Result" );
      Console.Write( "AND:" );
      PrintValues( myBA1.And( myBA2 ), 8 );
      Console.WriteLine();

      Console.WriteLine( "After AND" );
      Console.Write( "myBA1:" );
      PrintValues( myBA1, 8 );
      Console.Write( "myBA2:" );
      PrintValues( myBA2, 8 );
      Console.WriteLine();

      // Performing AND between BitArray instances of different sizes returns an exception.
      try  {
         BitArray myBA3 = new BitArray( 8 );
         myBA3[0] = myBA3[1] = myBA3[2] = myBA3[3] = false;
         myBA3[4] = myBA3[5] = myBA3[6] = myBA3[7] = true;
         myBA1.And( myBA3 );
      } catch ( Exception myException )  {
         Console.WriteLine("Exception: " + myException.ToString());
      }
   }

   public static void PrintValues( IEnumerable myList, int myWidth )  {
      int i = myWidth;
      foreach ( Object obj in myList ) {
         if ( i <= 0 )  {
            i = myWidth;
            Console.WriteLine();
         }
         i--;
         Console.Write( "{0,8}", obj );
      }
      Console.WriteLine();
   }
}


/*
This code produces the following output.

Initial values
myBA1:   False   False    True    True
myBA2:   False    True   False    True

Result
AND:   False   False   False    True

After AND
myBA1:   False   False   False    True
myBA2:   False    True   False    True

Exception: System.ArgumentException: Array lengths must be the same.
   at System.Collections.BitArray.And(BitArray value)
   at SamplesBitArray.Main()
*/

Imports System.Collections

Public Class SamplesBitArray    
    
    Public Shared Sub Main()
        
        ' Creates and initializes two BitArrays of the same size.
        Dim myBA1 As New BitArray(4)
        Dim myBA2 As New BitArray(4)
        myBA1(1) = False
        myBA1(0) = False
        myBA1(3) = True
        myBA1(2) = True
        myBA2(2) = False
        myBA2(0) = False
        myBA2(3) = True
        myBA2(1) = True
        
        ' Performs a bitwise AND operation between BitArray instances of the same size.
        Console.WriteLine("Initial values")
        Console.Write("myBA1:")
        PrintValues(myBA1, 8)
        Console.Write("myBA2:")
        PrintValues(myBA2, 8)
        Console.WriteLine()
        
        Console.WriteLine("Result")
        Console.Write("AND:")
        PrintValues(myBA1.And(myBA2), 8)
        Console.WriteLine()
        
        Console.WriteLine("After AND")
        Console.Write("myBA1:")
        PrintValues(myBA1, 8)
        Console.Write("myBA2:")
        PrintValues(myBA2, 8)
        Console.WriteLine()
        
        ' Performing AND between BitArray instances of different sizes returns an exception.
        Try
            Dim myBA3 As New BitArray(8)
            myBA3(0) = False
            myBA3(1) = False
            myBA3(2) = False
            myBA3(3) = False
            myBA3(4) = True
            myBA3(5) = True
            myBA3(6) = True
            myBA3(7) = True
            myBA1.And(myBA3)
        Catch myException As Exception
            Console.WriteLine("Exception: " + myException.ToString())
        End Try
    End Sub

    Public Shared Sub PrintValues(myList As IEnumerable, myWidth As Integer)
        Dim i As Integer = myWidth
        Dim obj As [Object]
        For Each obj In  myList
            If i <= 0 Then
                i = myWidth
                Console.WriteLine()
            End If
            i -= 1
            Console.Write("{0,8}", obj)
        Next obj
        Console.WriteLine()
    End Sub

End Class


' This code produces the following output.
' 
' Initial values
' myBA1:   False   False    True    True
' myBA2:   False    True   False    True
'
' Result
' AND:   False   False   False    True
'
' After AND
' myBA1:   False   False   False    True
' myBA2:   False    True   False    True
'
' Exception: System.ArgumentException: Array lengths must be the same.
'    at System.Collections.BitArray.And(BitArray value)
'    at SamplesBitArray.Main()

注釈

ビットごとの AND 演算は、両方のオペランドがtrue場合はtrueを返し、一方または両方のオペランドがfalse場合はfalseを返します。

このメソッドは、O(n)がnCount操作です。